Find two consecutive positive integers, sum of whose squares is 365.

Asked by Abhisek | 1 year ago |  85

##### Solution :-

Let us say, the two consecutive positive integers be x and x + 1.

Therefore, as per the given questions,

x2 + (x + 1)2 = 365

⇒ xx+ 1 + 2x = 365

⇒ 2x2 + 2x – 364 = 0

⇒ x– 182 = 0

⇒ x+ 14x – 13x – 182 = 0

⇒ x(x + 14) -13(x + 14) = 0

⇒ (x + 14)(x – 13) = 0

Thus, either, x + 14 = 0 or x – 13 = 0,

⇒ x = – 14 or x = 13

since, the integers are positive, so x can be 13, only.

x + 1 = 13 + 1 = 14

Therefore, two consecutive positive integers will be 13 and 14.

Answered by Pragya Singh | 1 year ago

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