Find the roots of the quadratic equations, if they exist, by the method of completing the square:$$4x^2 + 4\sqrt{3}x + 3 = 0$$

Asked by Pragya Singh | 1 year ago |  128

Solution :-

Converting the equation into a2+2ab+bform, we get,

⇒ (2x)2 + 2 × 2x × $$\sqrt{3}$$ + $$\sqrt({3})^2$$ = 0

⇒ (2x + $$\sqrt{3}$$)2 = 0

⇒ (2x + $$\sqrt{3}$$) = 0 and (2x + $$\sqrt{3}$$) = 0

Therefore, either $$x = \dfrac{\sqrt{3}}{2}or\; x = \dfrac{\sqrt{3}}{2}$$

Answered by Pragya Singh | 1 year ago

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