Find the roots of the quadratic equations given by applying the quadratic formula: 2x2 – 7x + 3 = 0

Asked by Pragya Singh | 1 year ago |  97

##### Solution :-

On comparing the given equation with ax2 + bx + c = 0, we get,

a = 2, b = -7 and c = 3

By using quadratic formula, we get,

$$x= \dfrac{-b±\sqrt{b^2-4ac}}{2a}$$

⇒ $$x= \dfrac{7±\sqrt{49-24}}{4}$$

⇒ $$x= \dfrac{7±\sqrt{25}}{4}$$

⇒ $$x= \dfrac{7±5}{4}$$

$$x= \dfrac{7+5}{4}\;or\; x= \dfrac{7-5}{4}$$

⇒ $$x= \dfrac{12}{4}\;or\; x= \dfrac{2}{4}$$

x = 3 or $$\dfrac{1}{2}$$

Answered by Abhisek | 1 year ago

### Related Questions

#### A natural number when increased by 12 equals 160 times its reciprocal. Find the number.

A natural number when increased by 12 equals 160 times its reciprocal. Find the number.

#### Find a natural number whose square diminished by 84 is equal to thrice of 8 more than the given number.

Find a natural number whose square diminished by 84 is equal to thrice of 8 more than the given number.

#### The numerator of a fraction is 3 less than the denominator. If 2 is added to both the numerator

The numerator of a fraction is 3 less than the denominator. If 2 is added to both the numerator and the denominator, then the sum of the new fraction and the original fraction is $$\dfrac{29}{20}$$ Find the original fraction.