Find the roots of the following equations: $$x-\dfrac{1}{x} = 3, x ≠ 0$$

Asked by Pragya Singh | 1 year ago |  107

##### Solution :-

Given,

$$\dfrac{x-1}{x}=3$$

⇒ x2 – 3x -1 = 0

On comparing the given equation with ax2 + bx + c = 0, we get

a = 1, b = -3 and c = -1

By using quadratic formula, we get,

⇒ $$x=\dfrac{(3±√9+4)}{2}$$

⇒ $$x=\dfrac{(3±√13)}{2}$$

$$x=\dfrac{(3+√13)}{2}or\; x=\dfrac{(3-√13)}{2}$$

Answered by Pragya Singh | 1 year ago

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