Given,

2x^{2} – 3x + 5 = 0

Comparing the equation with ax^{2} + bx + c = 0, we get

a = 2, b = -3 and c = 5

We know, Discriminant = b^{2} – 4ac

= ( – 3)^{2} – 4 (2) (5) = 9 – 40

= – 31

As you can see, b^{2} – 4ac < 0

Therefore, no real root is possible for the given equation, 2x^{2} – 3x + 5 = 0.

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