Radius of 1^{st} circle = 8 cm (given)

Area of 1^{st} circle = π(8)^{2} = 64π

Radius of 2^{nd} circle = 6 cm (given)

Area of 2^{nd} circle = π(6)^{2} = 36π

So,

The sum of 1^{st} and 2^{nd} circle will be = 64π+36π = 100π

Now, assume that the radius of 3^{rd} circle = R

Area of the circle 3^{rd} circle = πR^{2}

It is given that the area of the circle 3^{rd} circle = Area of 1^{st} circle + Area of 2^{nd} circle

Or, πR^{2} = 100πcm^{2}

R^{2} = 100cm^{2}

So, R = 10cm

Answered by Abhisek | 1 year agoProve that the area of a circular path of uniform width hsurrounding a circular region of radius r is πh(2r + h).

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