The radii of two circles are 8 cm and 6 cm respectively. Find the radius of the circle having area equal to the sum of the areas of the two circles.

Asked by Pragya Singh | 1 year ago |  110

1 Answer

Solution :-

Radius of 1st circle = 8 cm (given)

Area of 1st circle = π(8)2 = 64π

Radius of 2nd circle = 6 cm (given)

Area of 2nd circle = π(6)2 = 36π

So,

The sum of 1st and 2nd circle will be = 64π+36π = 100π

Now, assume that the radius of 3rd circle = R

Area of the circle 3rd circle = πR2

It is given that the area of the circle 3rd circle = Area of 1st circle + Area of 2nd circle

Or, πR2 = 100πcm2

R2 = 100cm2

So, R = 10cm

Answered by Abhisek | 1 year ago

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