Find the area of a quadrant of a circle whose circumference is 22 cm.

Asked by Abhisek | 1 year ago |  94

1 Answer

Solution :-

Circumference of the circle, C = 22 cm (given)

It should be noted that a quadrant of a circle is a sector which is making an angle of 90°.

Let the radius of the circle = r

As C = 2πr = 22,

R = \( \dfrac{22}{2}\)π cm = \( \dfrac{7}{2}\) cm

Area of the quadrant = \(\dfrac{θ}{360°}× πr^2 \)

Here, θ = 90°

So, A = \( \dfrac{90°}{360°}× π r^2 cm^2\)

= (\(\dfrac{49}{16}\)) π cm2

\( \dfrac{77}{8}\) cm2 = 9.6 cm2

Answered by Pragya Singh | 1 year ago

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