Find the area of a quadrant of a circle whose circumference is 22 cm.

Asked by Abhisek | 1 year ago |  94

Solution :-

Circumference of the circle, C = 22 cm (given)

It should be noted that a quadrant of a circle is a sector which is making an angle of 90°.

Let the radius of the circle = r

As C = 2πr = 22,

R = $$\dfrac{22}{2}$$π cm = $$\dfrac{7}{2}$$ cm

Area of the quadrant = $$\dfrac{θ}{360°}× πr^2$$

Here, θ = 90°

So, A = $$\dfrac{90°}{360°}× π r^2 cm^2$$

= ($$\dfrac{49}{16}$$) π cm2

$$\dfrac{77}{8}$$ cm2 = 9.6 cm2

Answered by Pragya Singh | 1 year ago

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