Find the area of the shaded region in the given figure, if ABCD is a square of side 14 cm and APD and BPC are semicircles.

Asked by Pragya Singh | 1 year ago |  68

1 Answer

Solution :-

Find the area of the shaded region in Fig., if ABCD is a square of side 14  cm and APD and BPC are semicircles.

Side of the square ABCD (as given) = 14 cm

So, Area of ABCD = a2

= 14×14 cm2 = 196 cm2

We know that the side of the square = diameter of the circle = 14 cm

So, side of the square = diameter of the semicircle = 14 cm

Radius of the semicircle = 7 cm

Now, area of the semicircle = \(\dfrac{πR^2}{2} \)

\( (\dfrac{22}{7}×7×7)\times\dfrac{1}{2} \)cm

= 77 cm2

Area of two semicircles = 2×77 cm= 154 cm2

Hence, area of the shaded region = Area of the Square – Area of two semicircles

= 196 cm-154 cm2

= 42 cm2

Answered by Abhisek | 1 year ago

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