In the given figure, OACB is a quadrant of circle with center O and radius 3.5 cm. If OD = 2 cm, find the area of the

(i) quadrant OACB,

(ii) shaded region.

In the figure, OACB is a quadrant of a circle with centre O and radius 3.5  cm. If OD = 2 cm, - CBSE Class 10 Maths - Learn CBSE Forum

Asked by Pragya Singh | 1 year ago |  146

1 Answer

Solution :-

Radius of the quadrant = 3.5 cm = \( \dfrac{7}{2}\) cm

(i) Area of quadrant OACB = \((\dfrac{πR^2}{4}) \) cm2

\( \dfrac{22}{7}\times \dfrac{7}{2}\times\dfrac{7}{2}\times \dfrac{1}{4} \) cm2

\(\dfrac{77}{8}\) cm2

 

(ii) Area of triangle BOD = \( \dfrac{1}{2}\times \dfrac{7}{2}\times 2\) cm2

\( \dfrac{7}{2}\) cm2

Area of shaded region = Area of quadrant – Area of triangle BOD

= (\( \dfrac{77}{8}\))-(\( \dfrac{7}{2}\)) cm= \( \dfrac{49}{8}\)cm2

= 6.125 cm2

Answered by Abhisek | 1 year ago

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