In the given figure, OACB is a quadrant of circle with center O and radius 3.5 cm. If OD = 2 cm, find the area of the

Asked by Pragya Singh | 1 year ago |  146

##### Solution :-

Radius of the quadrant = 3.5 cm = $$\dfrac{7}{2}$$ cm

(i) Area of quadrant OACB = $$(\dfrac{πR^2}{4})$$ cm2

$$\dfrac{22}{7}\times \dfrac{7}{2}\times\dfrac{7}{2}\times \dfrac{1}{4}$$ cm2

$$\dfrac{77}{8}$$ cm2

(ii) Area of triangle BOD = $$\dfrac{1}{2}\times \dfrac{7}{2}\times 2$$ cm2

$$\dfrac{7}{2}$$ cm2

Area of shaded region = Area of quadrant – Area of triangle BOD

= ($$\dfrac{77}{8}$$)-($$\dfrac{7}{2}$$) cm= $$\dfrac{49}{8}$$cm2

= 6.125 cm2

Answered by Abhisek | 1 year ago

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