Calculate the area of the designed region in the given figure common between the two quadrants of circles of radius 8 cm each.

Asked by Pragya Singh | 1 year ago |  198

##### Solution :-

AB = BC = CD = AD = 8 cm

Area of ΔABC = Area of ΔADC = $$(\dfrac{1}{2})×8×8 = 32 cm^2$$

$$\dfrac{1}{4}\times\dfrac{22}{7}×8^2$$

$$\dfrac{352}{7}cm^2$$

Area of shaded region = (Area of quadrant AECB – Area of ΔABC)

$$( \dfrac{352}{7}-32)+(\dfrac{352}{7}-32)cm^2$$

$$2×(\dfrac{352}{7}-32)cm^2$$

$$\dfrac{256}{7}cm^2$$

Answered by Abhisek | 1 year ago

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