Calculate the area of the designed region in the given figure common between the two quadrants of circles of radius 8 cm each.

Asked by Pragya Singh | 1 year ago |  198

1 Answer

Solution :-

AB = BC = CD = AD = 8 cm

Area of ΔABC = Area of ΔADC = \( (\dfrac{1}{2})×8×8 = 32 cm^2\)

Area of quadrant AECB = Area of quadrant AFCD 

\(\dfrac{1}{4}\times\dfrac{22}{7}×8^2 \)

\(\dfrac{352}{7}cm^2 \)

Area of shaded region = (Area of quadrant AECB – Area of ΔABC) 

= (Area of quadrant AFCD – Area of ΔADC)

\(( \dfrac{352}{7}-32)+(\dfrac{352}{7}-32)cm^2\) 

\( 2×(\dfrac{352}{7}-32)cm^2 \)

\(\dfrac{256}{7}cm^2 \)

Answered by Abhisek | 1 year ago

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