The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower is 30 .Find the height of the tower.

Asked by Abhisek | 1 year ago |  73

##### Solution :-

Let AB be the height of the tower and C is the point elevation which is 30 m away from the foot of the tower.

To Find: AB (height of the tower)

In right ABC

tan 30° = $$\dfrac{AB}{BC}$$

$$\dfrac{1}{\sqrt{3}}$$ = $$\dfrac{AB}{30}$$

⇒ AB = $$10\sqrt{3}$$

Thus, the height of the tower is $$10\sqrt{3}$$ m.

Answered by Pragya Singh | 1 year ago

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