Let AB be the lighthouse of height 75 m. Let C and D be the positions of the ships.

30° and 45° are the angles of depression from the lighthouse.

Draw a figure based on given instructions:

To Find: CD = distance between two ships

Step 1: From right triangle ABC,

tan 45° = \( \dfrac{AB}{BC}\)

1= \( \dfrac{75}{BC}\)

BC = 75 m

Step 2: Form right triangle ABD,

tan 30° = \( \dfrac{AB}{BD}\)

\( \dfrac{1}{\sqrt{3}}=\) \( \dfrac{75}{BD}\)

BD = \(75 \sqrt{3}\)

Step 3: To find measure of CD, use results obtained in step 1 and step 2.

CD = BD – BC = (\( 75 \sqrt{3}-75\))

= \( 75(\sqrt{3}-1)\)

The distance between the two ships is \( 75(\sqrt{3}-1)\;m\).

Answered by Abhisek | 1 year agoA balloon is connected to a meteorological ground station by a cable of length 215 m inclined at 60° to the horizontal. Determine the height of the balloon from the ground. Assume that there is no slack in the cable.

A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle of 30° with the ground. The distance from the foot of the tree to the point where the top touches the ground is 10 meters. Find the height of the tree.

The length of the shadow of a tower standing on level plane is found to be 2x meters longer when the sun’s attitude is 30° than when it was 30°. Prove that the height of tower is \( x(\sqrt{3}+1)\) meters.

A vertical tower stands on a horizontal plane and is surmounted by a flag staff of height 7m. From a point on the plane, the angle of elevation of the bottom of flag staff is 30° and that of the top of the flag staff is 45°. Find the height of the tower.

A man sitting at a height of 20 m on a tall tree on a small island in the middle of a river observes two poles directly opposite to each other on the two banks of the river and in line with foot of tree. If the angles of depression of the feet of the poles from a point at which the man is sitting on the tree on either side of the river are 60° and 30° respectively. Find the width of the river.