9 sec2A – 9 tan2A =

(A) 1                

(B) 9              

(C) 8                

(D) 0

Asked by Abhisek | 1 year ago |  62

1 Answer

Solution :-

Right answer is (B) 

Take 9 outside, and it becomes

9 sec2A – 9 tan2A

= 9 (sec2A – tan2A)

= 9×1 = 9   (∵ sec2 A – tan2 A = 1)

Therefore, 9 sec2A – 9 tan2A = 9

Answered by Pragya Singh | 1 year ago

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