In the figure, if ΔABE ≅ ΔACD, show that ΔADE ~ ΔABC.

Asked by Abhisek | 1 year ago |  69

##### Solution :-

Given, ΔABE ≅ ΔACD.

AB = AC [By CPCT] …………………….(i)

And, AD = AE [By CPCT] …………………(ii)

In ΔADE and ΔABC, dividing eq.(ii) by eq(i),

$$\dfrac{AD}{AB}=\dfrac{AE}{AC}$$

∠A = ∠A [Common angle]

ΔADE ~ ΔABC [SAS similarity criterion]

Answered by Sudhanshu | 1 year ago

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