In the figure, ABC and AMP are two right triangles, right angled at B and M respectively, prove that:

Asked by Abhisek | 1 year ago |  80

##### Solution :-

Given, ABC and AMP are two right triangles, right angled at B and M respectively.

(i) In ΔABC and ΔAMP, we have,

∠CAB = ∠MAP (common angles)

∠ABC = ∠AMP = 90° (each 90°)

ΔABC ~ ΔAMP (AA similarity criterion)

(ii) As, ΔABC ~ ΔAMP (AA similarity criterion)

If two triangles are similar then the corresponding sides are always equal,

Hence, $$\dfrac{CA}{PA}=\dfrac{BC}{MP}$$

Answered by Sudhanshu | 1 year ago

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