A vertical pole of a length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.

Asked by Abhisek | 1 year ago |  53

##### Solution :-

Given, Length of the vertical pole = 6m

Shadow of the pole = 4 m

Let Height of tower = h m

Length of shadow of the tower = 28 m

In ΔABC and ΔDEF,

∠C = ∠E (angular elevation of sum)

∠B = ∠F = 90°

ΔABC ~ ΔDEF (AA similarity criterion)

$$\dfrac{AB}{DF}=\dfrac{BC}{EF}$$ (If two triangles are similar corresponding sides are proportional)

$$\dfrac{6}{h}=\dfrac{4}{28}$$

⇒h = $$\dfrac{ (6×28)}{4}$$

⇒ h = 6 × 7

⇒ = 42 m

Hence, the height of the tower is 42 m.

Answered by Pragya Singh | 1 year ago

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