Given, a guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end.

Let AB be the pole and AC be the wire.

By Pythagoras theorem,

AC^{2} =^{ }AB^{2} + BC^{2}

24^{2} = 18^{2} + BC^{2}

BC^{2 }= 576 – 324

BC^{2 }= 252

BC^{ }= \(6 \sqrt{7}m\)

Therefore, the distance from the base is \( 6 \sqrt{7}m\).

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