A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

Asked by Pragya Singh | 1 year ago |  55

##### Solution :-

Given, a guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end.

Let AB be the pole and AC be the wire.

By Pythagoras theorem,

AC2 = AB2 + BC2

242 = 182 + BC2

BC= 576 – 324

BC= 252

BC $$6 \sqrt{7}m$$

Therefore, the distance from the base is $$6 \sqrt{7}m$$.

Answered by Abhisek | 1 year ago

### Related Questions

#### In an trapezium ABCD, it is given that AB ∥ CD and AB = 2CD. Its diagonals AC and BD

In an trapezium ABCD, it is given that AB ∥ CD and AB = 2CD. Its diagonals AC and BD intersect at the point O such that ar(∆AOB) = 84 cm2. Find ar(∆COD)

#### Find the length of the altitude of an equilateral triangle of side 2a cm.

Find the length of the altitude of an equilateral triangle of side 2a cm.

#### A ladder 10 m long reaches the window of a house 8 m above the ground.

A ladder 10 m long reaches the window of a house 8 m above the ground. Find the distance of the foot of the ladder from the base of the wall.