A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?

Asked by Pragya Singh | 1 year ago |  55

#### 1 Answer

##### Solution :-

Given, a guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end.

Let AB be the pole and AC be the wire.

By Pythagoras theorem,

AC2 = AB2 + BC2

242 = 182 + BC2

BC= 576 – 324

BC= 252

BC $$6 \sqrt{7}m$$

Therefore, the distance from the base is $$6 \sqrt{7}m$$.

Answered by Abhisek | 1 year ago

### Related Questions

#### In an trapezium ABCD, it is given that AB ∥ CD and AB = 2CD. Its diagonals AC and BD

In an trapezium ABCD, it is given that AB ∥ CD and AB = 2CD. Its diagonals AC and BD intersect at the point O such that ar(∆AOB) = 84 cm2. Find ar(∆COD)

Class 10 Maths Triangles View Answer

#### Find the length of the altitude of an equilateral triangle of side 2a cm.

Find the length of the altitude of an equilateral triangle of side 2a cm.

Class 10 Maths Triangles View Answer

#### A ladder 10 m long reaches the window of a house 8 m above the ground.

A ladder 10 m long reaches the window of a house 8 m above the ground. Find the distance of the foot of the ladder from the base of the wall.

Class 10 Maths Triangles View Answer

#### In the given figure, DE ∥ BC such that AD = x cm, DB = (3x + 4) cm, AE = (x + 3) cm

In the given figure, DE ∥ BC such that AD = x cm, DB = (3x + 4) cm, AE = (x + 3) cm and EC = (3x + 19) cm. Find the value of x.

Class 10 Maths Triangles View Answer

#### If ∆ABC ∼ ∆DEF such that 2 AB = DE and BC = 6 cm, find EF.

If ∆ABC ∼ ∆DEF such that 2 AB = DE and BC = 6 cm, find EF.

Class 10 Maths Triangles View Answer