Find the point on the x-axis which is equidistant from (2, – 5) and (- 2, 9).

Asked by Abhisek | 1 year ago |  101

##### Solution :-

To find a point on x-axis. Therefore, its y-coordinate will be 0. Let the point on x-axis be (x,0).

Consider A = (x, 0); B = (2, – 5) and C = (- 2, 9).

Simplify the above equation,

Remove square root by taking square both the sides, we get

(2 – x)+ 25 = [-(2 + x)]+ 81

(2 – x)+ 25 = (2 + x)+ 81

x+ 4 – 4x + 25 = x+ 4 + 4x + 81

8x = 25 – 81 = -56

x = -7

Therefore, the point is (- 7, 0).

Answered by Pragya Singh | 1 year ago

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