Find a relation between x and y such that the point (x, y) is equidistant from the point (3, 6) and (- 3, 4).

Asked by Abhisek | 1 year ago |  82

Solution :-

Point (x, y) is equidistant from (3, 6) and ( – 3, 4).

Squaring both sides, (x – 3)2+(y – 6)2 = (x + 3)2 +(y – 4)2

x+ 9 – 6x + y2+ 36 – 12y = x+ 9 + 6x + y+16 – 8y

36 – 16 = 6x + 6x + 12y – 8y

20 = 12x + 4y

3x + y = 5

3x + y – 5 = 0

Answered by Pragya Singh | 1 year ago

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