Find the coordinates of the point which divides the join of (- 1, 7) and (4, – 3) in the ratio 2:3.

Asked by Abhisek | 1 year ago |  101

1 Answer

Solution :-

Let P(x, y) be the required point. Using the section formula, we get

x = \( \dfrac{ (2×4 + 3×(-1))}{(2 + 3)}= \dfrac{(8 – 3)}{5}=1\)

y = \( \dfrac{(2×-3 + 3×7)}{(2 + 3)}= \dfrac{(-6 + 21)}{5}=3\)

Therefore, the point is (1, 3).

Answered by Pragya Singh | 1 year ago

Related Questions

In the determine whether the given quadratic equations have real roots and if so, And the roots 3x2 – 2x + 2 = 0

Class 10 Maths Coordinate Geometry View Answer

Find the point on x-axis which is equidistant from the points (-2, 5) and (2, -3).

Class 10 Maths Coordinate Geometry View Answer

Answer the following questions:-

(i) Show that the points A (5, 6), B (1, 5), C (2, 1) and D (6, 2) are the vertices of a square. 

(ii) Prove that the points A (2, 3), B (-2, 2), C (-1, -2) and D (3, -1) are the vertices of a square ABCD.

(iii) Name the type of triangle PQR formed by the point \( P(\sqrt{2} , \sqrt{2}), Q(- \sqrt{2}, – \sqrt{2)} and\; R (-\sqrt{6} , \sqrt{6} )\)

Class 10 Maths Coordinate Geometry View Answer

Find a point on the x-axis which is equidistant from the points (7, 6) and (-3, 4).

Class 10 Maths Coordinate Geometry View Answer

Find the coordinates of the circumcentre of the triangle whose vertices are (3, 0), (-1, -6) and (4, -1). Also, find its circumradius.
 

Class 10 Maths Coordinate Geometry View Answer