One mole of an ideal gas at standard temperature and pressure occupies 22.4 L (molar volume). What is the ratio of molar volume to the atomic volume of a mole of hydrogen? (Take the size of hydrogen molecule to be about 1 Å). Why is this ratio so large?

Asked by Abhisek | 1 year ago |  79

##### Solution :-

Radius = 0.5 A = 0.5 x 10-10 m

Volume = $$\dfrac{4}{3}\pi r^{3}$$

$$\dfrac{4}{3}\times \dfrac{22}{7}\times ( 0.5 \times 10^{-10})^3$$

= 0.524 x 10-30 m3

1 hydrogen mole contains 6.023 x 1023 hydrogen atoms.

Volume of 1 mole of hydrogen atom

= 6.023 x 1023 x 0.524 x 10-30

= 3.16 x 10-7 m3

Vm = 22.4 L = 22.4 x 10-3 m3

$$V m ​ ​ = \dfrac{22.4\times 10^{-3}}{3.16 \times 10^{-7}}$$ = = 7.1 x 104

Answered by Pragya Singh | 1 year ago

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