One mole of an ideal gas at standard temperature and pressure occupies 22.4 L (molar volume). What is the ratio of molar volume to the atomic volume of a mole of hydrogen? (Take the size of hydrogen molecule to be about 1 Å). Why is this ratio so large?

Asked by Abhisek | 1 year ago |  79

1 Answer

Solution :-

Radius = 0.5 A = 0.5 x 10-10 m

Volume = \( \dfrac{4}{3}\pi r^{3}\)

\(\dfrac{4}{3}\times \dfrac{22}{7}\times ( 0.5 \times 10^{-10})^3\)

= 0.524 x 10-30 m3

1 hydrogen mole contains 6.023 x 1023 hydrogen atoms.

Volume of 1 mole of hydrogen atom 

= 6.023 x 1023 x 0.524 x 10-30

= 3.16 x 10-7 m3

Vm = 22.4 L = 22.4 x 10-3 m3

\( V m ​ ​ = \dfrac{22.4\times 10^{-3}}{3.16 \times 10^{-7}} \) = = 7.1 x 104

 

Answered by Pragya Singh | 1 year ago

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