It is a well-known fact that during a total solar eclipse-the disk of the moon almost completely covers the disk of the Sun. From this fact and from the information you can gather from examples 2.3 and 2.4, determine the approximate diameter of the moon.

Asked by Abhisek | 1 year ago |  197

##### Solution :-

From examples 2.3 and 2.4  we get the following data

Distance of the Moon from Earth = 3.84 x 108 m

Distance of the Sun from Earth = 1.496 x 1011 m

Sun’s diameter = 1.39 x 109 m

Sun’s angular diameter,θ = 1920″ = 1920 x 4.85 x 10-6 rad

During a total solar eclipse, the disc of the moon completely covers the disc of the sun,

so the angular diameter of both the sun and the moon must be equal.

Therefore, Angular diameter of the moon, θ = 9.31 x 10-3 rad
The earth-moon distance, S = 3.8452 x 108 m

Therefore, the diameter of the moon, D = θ x S
= 9.31 x 10-3 x 3.8452 x 108 m = 35.796 x 105 m

Answered by Pragya Singh | 1 year ago

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