A police van moving on a highway with a speed of 30 km h–1 fires a bullet at a thief’s car speeding away in the same direction with a speed of 192 km h–1. If the muzzle speed of the bullet is 150 m s–1, with what speed does the bullet hit the thief’s car? (Note: Obtain that speed which is relevant for damaging the thief’s car).

Asked by Abhisek | 1 year ago |  92

1 Answer

Solution :-

Speed of the police van = 30 km/h = 30 x (\( \dfrac{5}{18}\)) = \( \dfrac{25}{3}\) m/s

Speed of a thief’s car = 192 km/h = 192 x (\( \dfrac{5}{18}\)) = \( \dfrac{160}{3}\) m/s

Muzzle Speed of  the bullet = 150 m/s

Speed of the bullet = speed of the police van + muzzle speed of  the bullet

= (\( \dfrac{25}{3}\))+ 150 =\( \dfrac{475}{3}\) m/s

The relative velocity of the bullet w.r.t the thief’s car is

v = Speed of the bullet – Speed of a thief’s car

= (\( \dfrac{475}{3}\)) – (\( \dfrac{160}{3}\)) = 105 m/s

The bullet hits the thief’s car at a speed of 105 m/s

Answered by Pragya Singh | 1 year ago

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