The following figure gives the x-t plot of a particle executing one-dimensional simple harmonic motion. (You will learn about this motion in more detail in Chapter 14). Give the signs of position, velocity and acceleration variables of the particle at t = 0.3 s, 1.2 s, – 1.2 s.

Asked by Abhisek | 1 year ago |  80

##### Solution :-

In S.H.M., acceleration, a = – ω2 x , ω is the angular frequency —-(1)

(i) At t = 0.3 s, x < 0 i.e., Position is negative. Moreover, as x is becoming more negative with time, it shows that velocity is negative (i.e., v < 0). However, using equation (1), acceleration will be positive.

(ii) At t = 1.2 s,  Positions and velocity will be positive. Acceleration will be negative.

(iii) At t = -1.2 s, Position, x is negative.  Velocity and acceleration will be positive.

Answered by Pragya Singh | 1 year ago

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