An aircraft executes a horizontal loop of radius 1 km with a steady speed of 900 km h-1.Compare its centripetal acceleration with the acceleration due to gravity.

Asked by Abhisek | 1 year ago |  76

1 Answer

Solution :-

Radius of the loop, r = 1 km = 1000 m

Speed, v = 900 km h-1 =\(900 \times \dfrac{5}{18}\)= 250 ms-1

Centripetal acceleration: \(a_{c} = \dfrac{v^{2}}{r}\)

=\(\dfrac{\left (250 \right )^{2}}{1000}\) = 62.5 ms-2

Acceleration due to gravity, g = 9.8 ms-2

\(\dfrac{a_{c}}{g} = \dfrac{62.5}{9.8}\) = 6.38

\(a_{c}= 6.38 \; g\)

Answered by Pragya Singh | 1 year ago

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