Height at which the aircraft is flying = 3400 m

Let A and B be the positions of the aircraft making an angle ∠AOB = 30°.

The perpendicular OC is drawn on AB. Here OC is the height of the aircraft which

is equal to 3400 m and ∠AOC = ∠COB = 15°.

In the ΔAOC, AC = OC tan 15°

= 3400 x 0.267 = 910.86 m

AB = AC + CB = AC + AC = 2 AC = 2 x 910.86 m

Speed of the aircraft = distance AB/time

= \( \dfrac{ (2 \times 910.86)}{10}\)= 182.17 m/s =182.2 m/s

Answered by Pragya Singh | 1 year ago**(a) **Show that for a projectile the angle between the velocity and the x-axis as a function of time is given by

\(\theta (t)=tan^{-1}(\dfrac{v_{0y-gt}}{v_{ox}})\)

**(b)** Shows that the projection angle θ_{0} for a projectile launched from the origin is given by

\(\theta_{0}=tan^{-1}(\dfrac{4h_{m}}{R})\)

where the symbols have their usual meaning

A cyclist is riding with a speed of 27 km/h. As he approaches a circular turn on the road of a radius of 80 m, he applies brakes and reduces his speed at the constant rate of 0.50 m/s every second. What is the magnitude and direction of the net acceleration of the cyclist on the circular turn?

A fighter plane flying horizontally at an altitude of 1.5 km with a speed of 720 km/h passes directly overhead an anti-aircraft gun. At what angle from the vertical should the gun be fired for the shell with muzzle speed 600 m s^{-1} to hit the plane? At what minimum altitude should the pilot fly the plane to avoid being hit? (Take g = 10 m s^{-2} ).

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Can we associate a vector with

**(i)** a sphere

**(ii)** the length of a wire bent into a loop

**(iii)** a plane area

Clarify for the same.