A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.

Asked by Pragya Singh | 1 year ago |  71

##### Solution :-

Given,

Mass, m = 5 kg

Force, F1 = 8N and F2 = 6N

The resultant force of the body

F = $$\sqrt{F_{1}^{2}+F_{2}^{2}}$$

$$=\sqrt{8^{2}+6^{2}}= \sqrt{64+36}$$

$$=10NF=F12​+F22​​$$

$$=82+62​=64+36​=10N$$

Acceleration, a = $$\dfrac{F}{m}$$

a = $$\dfrac{10}{5}$$ = 2m/s in the direction of the resultant force

The direction of the acceleration,

tan β = $$\dfrac{6}{8}$$ = 0.75

β = tan-1 (0.75)

β = 37 0 with 8N

Answered by Abhisek | 1 year ago

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