Figure shows the position-time graph of a particle of mass 4 kg. What is the

(a) force on the particle for t < 0, t > 4 s, 0 < t < 4 s?

(b) impulse at t = 0 and t = 4 s? (Consider one-dimensional motion only).

Asked by Pragya Singh | 1 year ago |  88

##### Solution :-

When t＜0, the distance covered by the particle is zero. Therefore, the force on the particle is zero.

When 0＜ t ＜4s, the particle is moving with a constant velocity. Therefore, the force will be zero.

When t＞4s, the particle remains at a constant distance. Therefore, the force of the particle will be zero.

Impulse at t = 0.

Here, u = 0

v = $$\dfrac{3}{4}$$ = 0.75 m/s

M = 4 kg

Impulse= total change in momentum = mv – mu

= m (v – u)

= 4 (0 – 0.75) = -3 kg m/s

Impulse at t= 4s

u = 0.75 m/s, v = 0

Impulse = m (v – u) = 4 (0 – 0.75) = -3 kg m/s

Answered by Abhisek | 1 year ago

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