Velocity of the ball = 54 km/h

The ball is deflected back such that the total angle = 45^{0}

The initial momentum of the ball is mucosӨ

= \( \dfrac{ (0.15 \times 54 \times 1000 \times cos 22. 5)}{3600}\)

= 0.15 x 15 x 0.9239 along NO

Final momentum of the ball = mucosӨ along ON

Impulse = change in the momentum = mucosӨ – (-mucosӨ)

= 2mucosӨ = 2 x 0.15 x 15 x 0.9239 = 4.16 kg.m/s

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