An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15°. What is the radius of the loop?

Asked by Abhisek | 1 year ago |  53

##### Solution :-

The speed of the aircraft executing the horizontal loop = 720 km/h

= 720 x ($$\dfrac{5}{18}$$) = 200 m/s

The angle of banking = 15°

tanθ= $$\dfrac{ v^2}{rg}$$ , we have

r = $$\dfrac{ v^2}{g\;tan\;θ }$$ = $$\dfrac{ (200 \times 200)}{(10 \times tan 15°)}$$

=$$\dfrac{ (200 \times 200)}{(10 \times 0.2679)}$$)= 14931 m

Answered by Pragya Singh | 1 year ago

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