Guitar strings X and Y striking the note ‘Ga’ are a little out of tune and give beats at 6 Hz. When the string X is slightly loosened and the beat frequency becomes 3 Hz. Given that the original frequency of X is 324 Hz, find the frequency of Y.

Asked by Pragya Singh | 1 year ago |  110

1 Answer

Solution :-

Given,

Frequency of  X, fX = 324 Hz

Frequency of  Y = fY

Beat’s frequency, n = 6 Hz

Also,

\(n = \left | f_{X}\pm f_{Y} \right |\)

\( 6 = 324 \pm f_{Y}\)

=  fY = 330 Hz or 318 Hz

As frequency drops with a decrease in tension in the string, thus fY cannot be 330 Hz
= fY = 318 Hz

Answered by Abhisek | 1 year ago

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