The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with simple harmonic motion with an angular frequency of 200 rad/min, what is its maximum speed?

Asked by Abhisek | 1 year ago |  79

1 Answer

Solution :-

Given

Angular frequency of the piston, 

ω = 200 rad/min

Stroke = 1.0 m

Amplitude, A = \( \dfrac{1.0}{2}\)

= 0.5 m

The maximum speed (vmax) of the piston is given by the relation:

vmax = 

= 200 x 0.5

We get,

= 100 m/min

Therefore, its maximum speed is 100 m/min

Answered by Abhisek | 1 year ago

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