The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with simple harmonic motion with an angular frequency of 200 rad/min, what is its maximum speed?

Asked by Abhisek | 1 year ago |  79

##### Solution :-

Given

Angular frequency of the piston,

ω = 200 rad/min

Stroke = 1.0 m

Amplitude, A = $$\dfrac{1.0}{2}$$

= 0.5 m

The maximum speed (vmax) of the piston is given by the relation:

vmax =

= 200 x 0.5

We get,

= 100 m/min

Therefore, its maximum speed is 100 m/min

Answered by Abhisek | 1 year ago

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