A thermodynamic system is taken from an original state to an intermediate state by the linear process shown in Figure.

Its volume is then reduced to the original value from E to F by an isobaric process. Calculate the total work done by the gas from D to E to F

Asked by Abhisek | 1 year ago |  177

##### Solution :-

Total work done by the gas from D to E to F = Area of ∆DEF

Area of ∆DEF = ($$\dfrac{1}{2}$$) x DE x EF

Where,

DF = Change in pressure

= $$\dfrac{ 600 N}{m^2}$$ – $$\dfrac{300N}{m^2}$$

We get,

$$\dfrac{300N}{m^2}$$

FE = Change in volume

= 5.0 m3 – 2.0 m3

We get,

= 3.0 m3

Area of ∆DEF = ($$\dfrac{1}{2}$$) x 300 x 3

On further calculation, we get,

= 450 J

Hence, the total work done by the gas from D to E to F is 450 J

Answered by Pragya Singh | 1 year ago

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