Two absolute scales A and B have triple points of water defined to be 200 A and 350 B. What is the relation between TA and TB ?

Asked by Pragya Singh | 1 year ago |  78

##### Solution :-

Given:

Triple point of water on absolute scale B, T2 = 400 B

Triple point of water on absolute scale A, T1 = 200 A

Triple point of water on Kelvin scale, TK = 273.15 K

273.15 K on the Kelvin scale is equivalent to 200 A on absolute scale A.

T1 = TK

200 A = 273.15 K

Thus, $$A = \dfrac{ 273.15 }{ 200 }$$

273.15 K on the Kelvin scale is equivalent to 350 B on absolute scale B.

⇒ T2 = TK

350 B = 273.15 K

Thus, $$B = \dfrac{ 273.15 }{ 350 }$$

Let, TA and Tbe the triple point of water on scale A and B respectively.

Thus, we have :
$$273.15 \times \dfrac{ T_{ A } }{ 200 } = 273.15 \times \dfrac{ T_{ B } }{ 200 }$$

Therefore, T: T= 4 : 7

Answered by Abhisek | 1 year ago

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