A 50 kg girl wearing high heel shoes balances on a single heel. The heel is circular with a diameter of 1.0 cm. What is the pressure exerted by the heel on the horizontal floor?

Asked by Pragya Singh | 1 year ago |  65

1 Answer

Solution :-

Radius of the heel, r = \( \dfrac{ d }{ 2 }​ = 0.005\; m\)

Mass of the lady, m = 50 kg

Area of the heel, A = πr2 = π (0.005)2

= 7.85 × 10-5 m2

Force on the floor due to the heel: F = mg 

= 50 × 9.8 = 490 N

Pressure exerted by the heel on the floor:

P = \( \dfrac{ F }{ A }\)​  = \( \dfrac{ 490 }{ 7.85 \times 10^{ -5 }} \)

P = \( 6.24 \times 10^{ 6 }Nm ^{-2}\)

Answered by Abhisek | 1 year ago

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