Compute the heat generated while transferring 96000 coulombs of charge in one hour through a potential difference of 50 V

Asked by Vishal kumar | 2 years ago |  201

##### Solution :-

The heat generated can be computed by Joule’s law as follows:

H = VIt

where, V is the voltage, V = 50 V

I is the current

t is the time in seconds, 1 hour = 3600 seconds

The amount of current can be calculated as follows:

$$Amount\, of \,Current = \frac{Amount\,of\,charge}{Time\,flow\,of\,charge}$$

Substituting the value, we get

$$I = \frac{96000}{3600}=26.66\,A$$

Now, to find the heat generated,

$$H=50\times26.66\times3600=4.8\times10^4\,J$$

The heat generated is $$4.8\times10^6\,J$$

Answered by Shivani Kumari | 2 years ago

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