Compute the heat generated while transferring 96000 coulombs of charge in one hour through a potential difference of 50 V

Asked by Vishal kumar | 1 year ago |  180

1 Answer

Solution :-

The heat generated can be computed by Joule’s law as follows:

H = VIt

where, V is the voltage, V = 50 V

I is the current

t is the time in seconds, 1 hour = 3600 seconds

The amount of current can be calculated as follows:

\( Amount\, of \,Current = \frac{Amount\,of\,charge}{Time\,flow\,of\,charge}\)

Substituting the value, we get

\(I = \frac{96000}{3600}=26.66\,A\)

Now, to find the heat generated,

\( H=50\times26.66\times3600=4.8\times10^4\,J\)

The heat generated is \( 4.8\times10^6\,J\)


Answered by Shivani Kumari | 1 year ago

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