Calculate the mass percent of different elements present in sodium sulphate $$Na_{2}SO_{4}$$.

Asked by Abhisek | 1 year ago |  77

##### Solution :-

Now for $$Na_{2}SO_{4}$$

Molar mass of $$Na_{2}SO_{4}$$

= [(2 x 23.0) + (32.066) + 4(16.00)]

=142.066 g

Formula to calculate mass percent of an element

$$\dfrac{Mass\;of\;that\;element\;in\;the\;compound}{Molar\;mass\;of\;the\;compound}\times 100$$

Therefore, mass percent of the sodium element:

$$\dfrac{46.0g}{142.066g}\times 100$$

= 32.379

= 32.4%

Mass percent of the sulphur element:

$$\dfrac{32.066g}{142.066g}\times 100$$

= 22.57

= 22.6%

Mass percent of the oxygen element:

=$$\dfrac{64.0g}{142.066g}\times 100$$

= 45.049

= 45.05%

Answered by Abhisek | 1 year ago

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