Calculate the mass of sodium acetate $$CH_{3}COONa$$ required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g $$mol^{-1}$$​.​​​​​​

Asked by Sudhanshu | 1 year ago |  86

##### Solution :-

0.375 Maqueous solution of $$CH_{3}COONa$$

= 1000 mL of solution containing 0.375 moles of $$CH_{3}COONa$$

Therefore, no. of moles of $$CH_{3}COONa$$ in 500 mL

$$\dfrac{0.375}{1000}\times 500$$

= 0.1875 mole

Molar mass of sodium acetate =$$82.0245\;g\;mol^{-1}$$

Therefore, mass that is required of $$CH_{3}COONa$$

=$$(82.0245\;g\;mol^{-1})(0.1875\;mole)$$

= 15.38 grams

Answered by Sudhanshu | 1 year ago

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