Calculate the mass of sodium acetate \( CH_{3}COONa\) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g \( mol^{-1}\)​.​​​​​​

Asked by Sudhanshu | 1 year ago |  86

1 Answer

Solution :-

0.375 Maqueous solution of \(CH_{3}COONa\)

= 1000 mL of solution containing 0.375 moles of \( CH_{3}COONa\)

Therefore, no. of moles of \( CH_{3}COONa\) in 500 mL

\(\dfrac{0.375}{1000}\times 500\)

= 0.1875 mole

Molar mass of sodium acetate =\(82.0245\;g\;mol^{-1}\)

Therefore, mass that is required of \( CH_{3}COONa\)

=\((82.0245\;g\;mol^{-1})(0.1875\;mole)\)

= 15.38 grams

Answered by Sudhanshu | 1 year ago

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