What is the concentration of sugar (C12H22O11) in mol L–1 if its 20 g are dissolved in enough water to make a final volume up to 2L?

Asked by Abhisek | 1 year ago |  113

1 Answer

Solution :-

Molarity (M) is as given by,

\(\dfrac{Number\;of\;moles\;of\;solute}{Volume\;of\;solution\;in\;Litres}\)

=\(\dfrac{\dfrac{Mass\;of\;sugar}{Molar\;mass\;of\;sugar}}{2\;L}\)

=\(\dfrac{\dfrac{20\;g}{[(12\;\times \;12)\;+\;(1\;\times \;22)\;+\;(11\;\times \;16)]g]}}{2\;L}\)

=\(\dfrac{\dfrac{20\;g}{342\;g}}{2\;L}\)

\(\dfrac{0.0585\;mol}{2\;L}\)

= 0.02925 mol\(L^{-1}\)

Therefore, Molar concentration = 0.02925 mol\(L^{-1}\)

Answered by Abhisek | 1 year ago

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