How many significant figures should be present in the answer of the following calculations?

(i) $$\dfrac{ 0.02856 \; \times \; 298.15 \; \times \; 0.112}{ 0.5785 }$$

(ii) 5 × 5.365

(iii) 0.012 + 0.7864 + 0.0215

Asked by Abhisek | 1 year ago |  55

##### Solution :-

(i) $$\dfrac{ 0.02856 \; \times \; 298.15 \; \times \; 0.112}{ 0.5785 }$$

Least precise no. of calculation = 0.112

Therefore, no. of significant numbers in the answer

= No. of significant numbers in the least precise no.

= 3

(ii) 5 × 5.365

Least precise no. of calculation = 5.365

Therefore, no. of significant numbers in the answer

= No. of significant numbers in 5.365

= 4

(iii) 0.012 + 0.7864 + 0.0215

As the least no. of decimal place in each term is 4, the no. of significant numbers in the answer is also 4.

Answered by Pragya Singh | 1 year ago

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