Calculate the wavelength, frequency and wave number of a light wave whose period is 2.0 × 10–10 s.

Asked by Pragya Singh | 1 year ago |  91

##### Solution :-

Frequency of the light wave

$$\dfrac{1}{Period}\\ \\ =\dfrac{1}{2.0\times 10^{-10}\, s}\\ \\ =5.0\times 10^{9}\, s^{-1 }$$

Wavelength of the light wave $$\lambda =c\nu$$

Where,

c denotes the speed of light, $$3\times 10^{8}\, m/s$$

Substituting the value of ‘c’ in the previous expression for $$\lambda$$

$$\lambda =\dfrac{3\times 10^{8}}{5.0\times 10^{9}}=6.0\times 10^{-2}m$$

Wave number $$(\bar{\nu })of light = \dfrac{1}{\lambda }=\dfrac{1}{6.0\times 10^{-2}}$$

$$=1.66\times 10^{1}\, m^{-1}=16.66\, m^{-1}$$

Answered by Abhisek | 1 year ago

### Related Questions

#### How many sub-shells are associated with n = 4?

(a) How many sub-shells are associated with n = 4?

(b) How many electrons will be present in the sub-shells having ms value of $$- \dfrac{1}{2}$$ for n = 4?

#### Indicate the number of unpaired electrons in:

Indicate the number of unpaired electrons in:

(a) P

(b) Si

(c) Cr

(d) Fe

(e) Kr

#### The unpaired electrons in Al and Si are present in 3p orbital.

The unpaired electrons in Al and Si are present in 3p orbital. Which electrons will experience more effective nuclear charge from the nucleus?

#### Among the following pairs of orbitals which orbital will experience the larger effective nuclear charge?

Among the following pairs of orbitals which orbital will experience the larger effective nuclear charge?

(i) 2s and 3s,

(ii) 4d and 4f,

(iii) 3d and 3p

#### The bromine atom possesses 35 electrons. It contains 6 electrons in 2p orbital, 6 electrons in 3p orbital

The bromine atom possesses 35 electrons. It contains 6 electrons in 2p orbital, 6 electrons in 3p orbital and 5 electrons in 4p orbital. Which of these electron experiences the lowest effective nuclear charge?