Calculate the wavelength, frequency and wave number of a light wave whose period is 2.0 × 10–10 s.

Asked by Pragya Singh | 1 year ago |  91

Solution :-

Frequency of the light wave

$$\dfrac{1}{Period}\\ \\ =\dfrac{1}{2.0\times 10^{-10}\, s}\\ \\ =5.0\times 10^{9}\, s^{-1 }$$

Wavelength of the light wave $$\lambda =c\nu$$

Where,

c denotes the speed of light, $$3\times 10^{8}\, m/s$$

Substituting the value of ‘c’ in the previous expression for $$\lambda$$

$$\lambda =\dfrac{3\times 10^{8}}{5.0\times 10^{9}}=6.0\times 10^{-2}m$$

Wave number $$(\bar{\nu })of light = \dfrac{1}{\lambda }=\dfrac{1}{6.0\times 10^{-2}}$$

$$=1.66\times 10^{1}\, m^{-1}=16.66\, m^{-1}$$

Answered by Abhisek | 1 year ago

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