What is the number of photons of light with a wavelength of 4000 pm that provides 1J of energy?

Asked by Pragya Singh | 1 year ago |  88

1 Answer

Solution :-

Energy  of one photon (E) = \(h\nu\)

Energy of ‘n’ photons \(E_{n} = nh\nu \Rightarrow n=\dfrac{E_{n}\lambda }{hc}\)

Where, \(\lambda\) is the wavelength of the photons = 4000 pm 

=\(4000\times 10^{-12}\, m\)

c denotes the speed of light in vacuum =\(3\times 10^{8}\, m/s\)

h is Planck’s constant, whose value is \(6.626\times 10^{-34}\, Js\)

Substituting these values in the expression for n:

\(n=\dfrac{1\times (4000\times 10^{-12})}{(6.626\times 10^{-34})(3\times 10^{8})}=2.012\times 10^{16}\)

Hence, the number of photons with a wavelength of 4000 pm and energy of 1 J are

\(2.012\times 10^{16}\)

Answered by Abhisek | 1 year ago

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