What is the number of photons of light with a wavelength of 4000 pm that provides 1J of energy?

Asked by Pragya Singh | 1 year ago |  88

##### Solution :-

Energy  of one photon (E) = $$h\nu$$

Energy of ‘n’ photons $$E_{n} = nh\nu \Rightarrow n=\dfrac{E_{n}\lambda }{hc}$$

Where, $$\lambda$$ is the wavelength of the photons = 4000 pm

=$$4000\times 10^{-12}\, m$$

c denotes the speed of light in vacuum =$$3\times 10^{8}\, m/s$$

h is Planck’s constant, whose value is $$6.626\times 10^{-34}\, Js$$

Substituting these values in the expression for n:

$$n=\dfrac{1\times (4000\times 10^{-12})}{(6.626\times 10^{-34})(3\times 10^{8})}=2.012\times 10^{16}$$

Hence, the number of photons with a wavelength of 4000 pm and energy of 1 J are

$$2.012\times 10^{16}$$

Answered by Abhisek | 1 year ago

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