What is the maximum number of emission lines when the excited electron of a H atom in n = 6 drops to the ground state?

Asked by Pragya Singh | 1 year ago |  119

##### Solution :-

A total number of  15 lines (5 + 4 + 3 + 2 + 1) will be obtained in this hydrogen emission spectrum.

Total no. of spectral lines emitted when an electron initially in the ‘nth‘ level drops down to the ground state can be calculated using the following expression:

$$\dfrac{n(n-1)}{2}$$

Since n = 6, total no. spectral lines = $$\dfrac{6(6-1)}{2}=15$$

Answered by Abhisek | 1 year ago

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