What are the atomic numbers of elements whose outermost electrons are represented by

(a) \( 3s^1\)

(b) \( 2p^3\) and

(c) \( 3p^5\)

Asked by Pragya Singh | 1 year ago |  78

1 Answer

Solution :-

(a) 3s1

Complete electronic configuration: 1s2 2s2 2p6 3s1.

Total no. electrons in the atom = 2 + 2 + 6 + 1 = 11

 ∴the element’s atomic number is 11

(b) 2p3

Complete electronic configuration: 1s2 2s2 2p3 .

Total no. electrons in the atom =2 + 2 + 3 = 7

∴the element’s atomic number is 7

 

(c) 3p5

Complete electronic configuration: 1s2 2s2 2p6 3s2 3p5 .

Total no. electrons in the atom = 2 + 2 + 6 + 2 + 5 = 17

∴the element’s atomic number is 17

Answered by Pragya Singh | 1 year ago

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