How many electrons in an atom may have the following quantum numbers?

(a) n = 4, m=$$-\dfrac{1}{2}$$

(b) n = 3, l = 0

Asked by Pragya Singh | 1 year ago |  105

##### Solution :-

(a) If n is the principal quantum number, the total number of electrons in the atom = 2n2

For n = 4, Total no. electrons = 2 (4)2 = 32

Electron configuration for an atom with 32 electrons: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 .

Hence, all the electrons are paired.

No. electrons having n = 4 and m

=$$-(\dfrac{1}{2})$$ = 16

(b) n = 3, l = 0 indicates the 3s orbital. Therefore, no. electrons with n = 3 and l = 0 is 2.

Answered by Pragya Singh | 1 year ago

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