If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across the length of the scale of length 20 cm long.

Asked by Pragya Singh | 1 year ago |  66

##### Solution :-

1 m = 100 cm

1 cm = 10–2 m

Length of the scale = 20 cm

=$$20\times 10^{-2}\, m$$

Diameter of one carbon atom = 0.15 nm

=$$0.15\times 10^{-9}\, m$$

Space occupied by one carbon atom $$0.15\times 10^{-9}\, m$$

∴No. carbon atoms that can be placed in a straight line

$$\dfrac{20\times 10^{-2}m}{0.15\times 10^{-9}m}\\$$

$$=133.33\times 10^{7}\\ \\ =1.33\times 10^{9}$$

Answered by Abhisek | 1 year ago

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