$$2\times 10^{8}\, m$$ atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

Asked by Pragya Singh | 1 year ago |  74

Solution :-

Length of the arrangement = 2.4 cm

No. carbon atoms present = 2 × 108

The diameter of the carbon atom

=$$\dfrac{2.4\times 10^{-2}m}{2\times 10^{8}m}\\ \\$$

$$=1.2\times 10^{-10}m$$

$$\;Radius \;of \;carbon\; atom$$

$$=\dfrac{Diameter}{2}\\ \\ =\dfrac{1.2\times 10^{-10}m}{2}\\ \\ =6.0\times 10^{-11}m$$

Answered by Sudhanshu | 1 year ago

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