In Milikan’s experiment, the static electric charge on the oil drops has been obtained by shining X-rays. If the static electric charge on the oil drop is

$$-1.282 \times 10^{-18}C$$ , calculate the number of electrons present on it.

Asked by Pragya Singh | 1 year ago |  128

##### Solution :-

Charge held by the oil drop

$$=1.282 \times 10^{-18}C$$

Charge held by one electron

$$=1.6022 \times 10^{-19}C$$

Therefore, No. electrons present in the drop of oil

$$\dfrac{1.282\times 10^{-18}C}{1.6022\times 10^{-19}C}\\ \\$$

$$=0.8001\times 10^{1}\\ \\ =8.0$$

Answered by Abhisek | 1 year ago

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