An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

Asked by Abhisek | 1 year ago |  55

1 Answer

Solution :-

Let the no. electrons in the negatively charged ion be x.

Then, no. neutrons present = x + 11.1% of x

 = x + 0.111 x = 1.111 x

No. electrons present in the neutral atom = (x – 1)

(When an ion carries a negative charge, it carries an extra electron)

No. protons present in the neutral atom = x – 1

Given, mass number of the ion = 37

(x – 1) + 1.111x = 37

2.111x = 38

x = 18

Therefore, The symbol of the ion is \(_{17}^{37}\textrm{Cl}^{-}\)

Answered by Sudhanshu | 1 year ago

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