An ion with mass number 56 contains 3 units of positive charge and 30.4% more neutrons than electrons. Assign the symbol to this ion.

Asked by Abhisek | 1 year ago |  67

##### Solution :-

Let the total no. electrons present in $$A^{3+}$$ be x.

Now, total no. neutrons in it = x + 30.4% of x = 1.304 x

Since the ion has a charge of +3 , no. electrons in neutral atom = x + 3

Therefore, no. protons in neutral atom = x + 3

The Mass number of the ion is 56 (Given)

Therefore, (x+3) + (1.304x) = 56

2.304x = 53

$$x=\dfrac{53}{2.304}$$

X = 23

Therefore, no. protons = x + 3 = 23 + 3 = 26

The ion is $$_{26}^{56}\textrm{Fe}^{3+}$$

Answered by Pragya Singh | 1 year ago

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